Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Skill Practice - Page 164: 19

$x=-\frac{1}{2}$ and $y=\frac{1}{6}$

$5x-3y=-3$ $/\times(2)$ to get rid of the $y$ $2x+6y=0$ _________________ $10x-6y=-6$ $2x+6y=0$ _________________ $12x=-6$ $x=-\frac{6}{12}$ $x=-\frac{1}{2}$ when $x=-\frac{1}{2}$... $2(-\frac{1}{2})+6y=0$ $6y-1=0$ $6y=1$ $y=\frac{1}{6}$