Chapter 3 Linear Systems and Matrices - 3.1 Solve Linear Systems by Graphing - 3.1 Exercises - Skill Practice - Page 157: 33

The solutions are $(-4,2)$ and $(4,2)$.

Given: $y = |x|-2$ $y=2$ The graphs intersect at two points: $(-4,2)$ and $(4,2)$. Check again: $y = |x|-2$ $2=|4|-2$ $2=4-2$ $2=2$ $y = |x|-2$ $2=|-4|-2$ $2=4-2$ $2=2$ The solutions are $(-4,2)$ and $(4,2)$.