Chapter 3 Linear Systems and Matrices - 3.1 Solve Linear Systems by Graphing - 3.1 Exercises - Mixed Review - Page 158: 51

$y=-\frac{16}{9}x-\frac{8}{3}$ when $x=-6$ then $y=8$

$16x+9y=-24$ $9y=-16x-24$ $y=-\frac{16}{9}x-\frac{24}{9}=-\frac{16}{9}-\frac{8}{3}$ when $x=-6$ $y=-\frac{16}{9}\times(-6)-\frac{8}{3}=\frac{32}{3}-\frac{8}{3}=\frac{24}{3}$ $y=8$