Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 2 Linear Equations and Functions - 2.4 Write Equations of Lines - Problem Solving Workshop - Practice - Page 105: 2

Answer

$y=\dfrac{45}{13}x+\dfrac{60}{13}$

Work Step by Step

We have to determine the equation $$y=mx+b,$$ where $y$ represents the number of calories burnt per hour $x$ represents the swimmer's weight. We are given two points on the graph of the line describing the equation: $(120,420)$ and $(172,600)$. $\textbf{First method}$ We will write the equation in point-slope form, then rewrite it in slope-intercept form. We calculate the slope: $$m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{600-420}{172-120}=\dfrac{45}{13}.$$ We determine the point-slope equation using the slope $m$ and one of the points, $(120,420)$: $$y-y_0=m(x-x_0)$$ $$y-420=\dfrac{45}{13}(x-120)$$ Rewrite the equation in slope-intercept form: $$y=\dfrac{45}{13}x+\dfrac{60}{13}.$$ $\textbf{Second method}$ We will calculate the slope of the line, then its $y$-intercept and finally write the equation in slope-intercept form. We calculate the slope: $$m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{600-420}{172-120}=\dfrac{45}{13}.$$ Substitute the slope and the coordinates of one point, for example $(120,420)$, into the slope-intercept form and solve for $b$: $$\begin{align*} y&=mx+b\\ 420&=\dfrac{45}{13}(120)+b\\ b&=420-\dfrac{5400}{13}=\dfrac{60}{13}. \end{align*}$$ Substitute $m$ and $b$ into the slope-intercept form: $$y=\dfrac{45}{13}x+\dfrac{60}{13}.$$
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