Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 2 Linear Equations and Functions - 2.4 Write Equations of Lines - 2.4 Exercises - Skill Practice - Page 102: 39

Answer

Answer $C$: $(7,7)$

Work Step by Step

1) determine the equations of the line with slope $-6$ and passing through the point $(9,-5)$ 2) check if the points belong to the line. $\textbf{1) Determine the equation of the line}$ The equation of the line with slope $m$ and passing through the point $(x_0,y_0)$ is: $$y-y_0=m(x-x_0).$$ Substitute $m=-6$ and $(x_0,y_0)=(9,-5)$ in the above equation: $$\begin{align*} y-(-5)&=-6(x-9)\\ y+5&=-6x+54\\ y&=-6x+54-5\\ y&=-6x+49. \end{align*}$$ $\textbf{2) Check which of the points belong to the line}$ We take each point and substitute the coordinates of the point in the equation of the line. A) $(6,10)$ $$\begin{align*} 10&\stackrel{?}{=}-6(6)+49\\ 10&\stackrel{?}{=}13\\ 10&\not=13. \end{align*}$$ B) $(6,6)$ $$\begin{align*} 6&\stackrel{?}{=}-6(6)+49\\ 6&\stackrel{?}{=}13\\ 6&\not=13. \end{align*}$$ C) $(7,7)$ $$\begin{align*} 7&\stackrel{?}{=}-6(7)+49\\ 7&\stackrel{?}{=}-42+49\\ 10&=7\checkmark. \end{align*}$$ D) $(6,-4)$ $$\begin{align*} -4&\stackrel{?}{=}-6(6)+49\\ -4&\stackrel{?}{=}13\\ -4&\not=13. \end{align*}$$ So the point which fits is $(7,7)$. The correct answer is Answer $C$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.