Answer
$2+\sqrt3$
Work Step by Step
Using the given formula and the known values: $\tan (5\pi/12)=\frac{\tan(\pi/4)-\tan (\pi/6)}{1+\tan(\pi/4)\tan (\pi/6)}=\frac{1-\frac{1}{\sqrt3}}{1-1\frac{1}{\sqrt3}}=2+\sqrt3$
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