Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.7 Apply Double-Angle and Half-Angle Formulas - 14.7 Exercises - Mixed Review - Page 962: 65

Answer

$$x=\frac{1}{3}$$

Work Step by Step

Simplifying the equation, we obtain: $$\left(\sqrt{6x+7}\right)^2=3^2 \\ 6x+7=9 \\ x=\frac{1}{3}$$
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