Answer
$y =3 \sin 2x$
Work Step by Step
General solution for Trigonometric functions $sine$ and $cosine$ that model a sinusoid is as follows: $y=A \sin B (x-h) +k $ and $y=A \cos B (x-h)+k$
We can see from the graph that it passes through the origin and defines the $Sine$ function. Here, the amplitude is $a=3$, that is $3 \sin $
Since, the time period for a trigonometric function is $2 \pi/b$ and here $B=2$
Thus, we have $y =3 \sin 2x$