Answer
$\sin^2x$
Work Step by Step
Using the given identities: $\frac{\cos(\pi/2-x)}{\csc x}=\frac{\cos(\pi/2-x)}{\csc x}=\frac{\sin x}{\frac{1}{\sin x}}=\sin^2x$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.3 Verify Trigonometric Identities - 14.3 Exercises - Skill Practice - Page 928: 15
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