Answer
$$y=-5tan(x-\frac{\pi}{4})$$
Work Step by Step
In the last section, the given functions were sine and cosine functions in the form $y=asin(bx)$ and $y=acos(bx)$. Note, the only difference between sine and cosine functions is that, when not shifted, cosine functions are at their maximum amplitude at $x=0$, while sine functions are at $0$ at this point. Note, $\mid a\mid $ is the amplitude of the functions, and $\frac{2\pi}{b}$ is the period of these functions. All of this is still true. However, now the functions also can be shifted by $h$ units to the right and $k$ units up, as noted on page 915. Recall, it is necessary to pay attention to the sign of $h$ and $k$. (Do not forget that there is a negative in front of $h$!)
Thus, we see that the equation becomes:
$$y=-5tan(x-\frac{\pi}{4})$$
