Answer
$$A=4\sqrt{21}$$
Work Step by Step
By Heron's Formula, we know:
$$A=\sqrt{s(s-a)(s-b)(s-c)}$$
Where:
$$s=\frac{a+b+c}{2}$$
Thus, we find:
$$s=\frac{5+8+11}{2}=12 \\ A=\sqrt{12\left(12-5\right)\left(12-8\right)\left(12-11\right)} \\ A=4\sqrt{21}$$