Answer
$\approx279.1$
Work Step by Step
The area of a triangle with sides $a,b,c$ is: $\sqrt{s(s-a)(s-b)(s-c)}$ where $s=0.5(a+b+c)$.
Hence here $s=0.5(27+21+37)=42.5$, thus the area: $\sqrt{42.5(42.5-27)(42.5-21)(42.5-37)}\approx279.1$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.6 Apply the Law of Cosines - 13.6 Exercises - Quiz for Lessons 13.5-13.6 - Page 894: 12
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