Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.6 Apply the Law of Cosines - 13.6 Exercises - Problem Solving - Page 894: 48

Answer

See below

Work Step by Step

Angle $A=90^\circ-55^\circ-7^\circ=28^\circ$ Using law of cosines: $$a^2=b^2+c^2-2bc\cos A\\a=\sqrt 890^2+470^2-2\times890\times470\cos 28^\circ\approx523.76$$
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