Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - Guided Practice for Example 1 - Page 882: 2

Answer

See below.

Work Step by Step

$C=180-51-44=85^\circ$. Using the law of sines, $\frac{a}{\sin51^\circ}=\frac{11}{\sin85^\circ}\\a=\frac{11\sin51^\circ}{\sin85^\circ}\approx8.58$ $\frac{b}{\sin44^\circ}=\frac{11}{\sin85^\circ}\\b=\frac{11\sin44^\circ}{\sin85^\circ}\approx7.67$
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