Answer
$x \pm 4$
Work Step by Step
We have $3x+16=x(x+3)$ ...(1)
Re-write as: $3x+16=x^2+3x$
or, $x^2-16 =0 \implies (x-4)(x+4)=0$
or, $x \pm 4$
and $x \ne -3, \dfrac{-16}{3}$
The solutions are not undefined values.
So, $x \pm 4$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Mixed Review - Page 830: 54
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