Answer
$16.5 ft/s$
Work Step by Step
Here, we have $\theta=18^{\circ}$ and $d=5$
We know that $d=\dfrac{v^2}{32} \sin (2 \theta)$
$5=\dfrac{v^2}{32} \sin 2 (18^{\circ})$
This implies that
$v^2=272.21$
Thus, $v= \sqrt {272.21}=16.5 ft/s$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Problem Solving - Page 871: 36
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