Answer
$390$
Work Step by Step
$\sum_{i=1}^{15} (3i+1)=3 \times \sum_{i=1}^{15} i+\sum_{i=1}^{15} (1)$
$=3 \times \dfrac{(15) \times (15+1)}{2}+1 \times (15)$
$=3 \times \dfrac{(15) \times (16)}{2}+(1) \times (15)$
$=360+30$
$=390$
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