Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.2 Define General Angles and Use Radian Measure - 13.2 Exercises - Quiz for Lessons 13.1 and 13.2 - Page 865: 2

Answer

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Work Step by Step

Given: $A=25$ degrees $b=10$ Thus, $C=90$ It is a right triangle. Hence, the sum of two non-right angles of a triangle is 90 degrees: $B=90-A=90-25=65$ degrees We know $\tan A=\frac{a}{b}\\ \rightarrow a=b\tan A=10\times \tan 25\approx 4.66$ Apply the Pythagorean theorem to find c: $a^2+b^2=c^2\\c=\sqrt a^2+b^2\\c=\sqrt 10^2+(10\tan25)^2\approx11.03$
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