Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.2 Define General Angles and Use Radian Measure - 13.2 Exercises - Mixed Review - Page 865: 70

Answer

$126$

Work Step by Step

The formula for combinations is given by $$nC_r=\frac{n!}{r!(n-r)!}$$ Substitute $n=9,r=5$ in the above formula. $\begin{aligned}9C_5&=\frac{9!}{5!(9-5)!}\\&=\frac{9!}{5!4!}\\9C_5&=126\end{aligned}$
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