Answer
$126$
Work Step by Step
The formula for combinations is given by
$$nC_r=\frac{n!}{r!(n-r)!}$$
Substitute $n=9,r=5$ in the above formula.
$\begin{aligned}9C_5&=\frac{9!}{5!(9-5)!}\\&=\frac{9!}{5!4!}\\9C_5&=126\end{aligned}$
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