Answer
$53612.7 ft$
Work Step by Step
Let $x$ be the horizontal distance of the airplane from town $1$.
Here,we have $\tan 65^{\circ}=\dfrac{25000 ft}{x}$
This gives: $x=25,000 \times \cot 25^{\circ}$
Now,
$x=53612.7 ft$
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