Answer
765
Work Step by Step
Determine the sum of the special pattern:
$$\sum^{15}_{n=1} (6n+3)=\sum^{15}_{n=1}6n+\sum^{15}_{n=1}3\\=6\sum^{15}_{n=1}n+15\times3\\=6\frac{15\times(15+1)}{2}+45\\=765$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Standardized Test Practice - Gridded Answer - Page 847: 14
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