Answer
$7714$
Work Step by Step
We know that $\sum_{i=1}^n(n^2)=\frac{n(n+1)(2n+1)}{6}$
Hence $\sum_{i=1}^{28}(i^2)=\frac{28(28+1)(2(28)+1)}{6}=7714$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Chapter Test - Page 843: 14
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