Answer
See below.
Work Step by Step
We know that $f(x_1)=f(2)=x_2=2$, thus $f(x_2)=f(2)=x_3=2\ne8$.
Therefore, the function does not exist.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.5 Use Recursive Rules with Sequences and Functions - 12.5 Exercises - Skill Practice - Page 831: 41
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