Answer
$\frac{13}{99}$
Work Step by Step
Following the example: $0.1313...=13(0.01)+13(0.01)^2+...=\frac{a_1}{1-r}=\frac{13(0.01)}{1-0.01}=\frac{0.13}{0.99}=\frac{13}{99}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.4 Find Sums of Infinite Geometric Series - Guided Practice for Examples 4 and 5 - Page 822: 8
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