Answer
$ |x| \lt 0.25$ and $S_n=\dfrac{1}{1-4x}$
Work Step by Step
Here, we have $a_n= a_1 r^{n-1}$ for the Geometric series.
The sum of an infinite Geometric Series can be found using: $S_n=\dfrac{a_1}{1-r}$
First term $a_1=1$ and Common ratio $r=4x$
We know that for an infinite Geometric Sequence to converge: $|r| \lt 1 $ This gives: $|4x| \lt 1$
$\implies |x| \lt 0.25$
Thus, we have $S_n=\dfrac{1}{1-4x}$
Hence, $ |x| \lt 0.25$ and $S_n=\dfrac{1}{1-4x}$