Answer
$130$
Work Step by Step
$\displaystyle \sum_{k=3}^{7}(k^{2}-1)=(3^{2}-1)+(4^{2}-1)+(5^{2}-1)+(6^{2}-1)+(7^{2}-1)$
$=8+15+24+35+48$
$=130$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - Guided Practice for Examples 5 and 6 - Page 797: 11
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