Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Mixed Review of Problem Solving - Lessons 11.3-11.5 - Page 782: 8c

Answer

$[12.82,17.18]$

Work Step by Step

We found that the margin of error in part b is: $M=\pm 0.0218=2.18\%$ To get the interval, we perform $15-2.18=12.82\\15+2.18=17.18$ Hence, the interval is $[12.82,17.18]$
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