Answer
$2.28\%$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{16-12}{2}=2$
Then, using the table: $P(x\geq16)\approx P(z\geq2)=1-P(z\leq2)=1-9772=0.0228=2.28\%$