Answer
See below.
Work Step by Step
The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean: $\frac{132+130+130+121+115+108}{6}\approx122.667$, the median is the average of the middle $2$ in the sequence $132, 130, 130, 121, 115, 108$, which is: $(130+121)/2=125.5$, the mode is $130$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the range is: $132-108=24$ and the standard deviation is: $\sqrt{\frac{(132-122.667)^2+(130-122.667)^2+...+(108-122.667)^2}{6}}\approx 8.8632$
When every value of a data set is multiplied by a constant, the new mean, median, mode, range, and standard deviation can be obtained by multiplying each original value by the constant. Here the constant is $0.5$, hence the mean: $122.667\cdot 0.5=61.333$, the median: $125.5\cdot 0.5=62.75$, the mode: $130\cdot 0.5=65$, the range:$24\cdot 0.5=12$, and the standard deviation: $8.8632\cdot 0.5=4.4316$.
