Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.2 Apply Transformations to Data - 11.2 Exercises - Problem Solving - Page 754: 23c

Answer

See below

Work Step by Step

We will transform the data set using this formula: $$C=\frac{5}{9}(F-32)$$ The new values are: 74.5 becomes $\frac{5}{9}(74.5-32)=23.61$ 81.9 becomes $\frac{5}{9}(81.9-32)=27.72$ 72.5 becomes $\frac{5}{9}(72.5-32)=22.5$ 73.4 becomes $\frac{5}{9}(73.4-32)=23$ 78.4 becomes $\frac{5}{9}(78.4-32)=25.7$ 72.6 becomes $\frac{5}{9}(72.6-32)=22.5$ 76.8 becomes $\frac{5}{9}(76.8-32)=24.8$ 77.6 becomes $\frac{5}{9}(77.6-32)=25.3$ 72 becomes $\frac{5}{9}(72-32)=22.2$ 79.2 becomes $\frac{5}{9}(79.2-32)=26.2$ 76.2 becomes $\frac{5}{9}(76.2-32)=24.5$ Hence, the transformed data set is: $23.61,27.72,22.5,23,25.7,22.5,24.8,23.61,25.3,22.2,26.2,24.5$
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