Chapter 11 Data Analysis and Statistics - 11.2 Apply Transformations to Data - 11.2 Exercises - Mixed Review - Page 755: 27

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Given: $3x^2-13x+8=0$ We can see $a=3\\b=-13\\c=8$ Applying the quadratic formula, we found: $x_1=\frac{-(-13)+\sqrt (-13)^2-4(3)(8)}{2(3)}\approx3.59\\ x_2=\frac{-(-13)-\sqrt (-13)^2-4(3)(8)}{2(3)}\approx 0.7427$