Answer
See below
Work Step by Step
The mean when the outlier is included:
$\bar x=\frac{70+55+54+75+60+58+55+6+62+68+94+55+82+69+74}{12}=62.06\\\sigma=\sqrt \frac{5288.9376}{16}=18.1813$
Since $|\frac{6-62.06}{18.1813}|\approx3.0834\gt3$, 6 is an outlier.