Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is included:
$\bar x=\frac{86.5+84.95+84.84+84.13+83.31+83.25+83.14+83.01+80.59+80.28+79.43+74.36}{12}\approx 82.32\\ Median =\frac{83.25+83.14}{2}=83.195\\Mode =none\\Range=86.50-74.36=12.14\\\sigma =\sqrt \frac{(86.5-82.32)^2+(84.95-82.32)^2+(84.84-82.32)^2+(188-186.71)^2+...+(74.36-82.32)^2}{12}=3.11$