Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.6 Construct and Interpret Binomial Distributions - 10.6 Exercises - Quiz for Lessons 10.5-10.6 - Page 730: 1

Answer

$\frac{27}{190}$

Work Step by Step

In this case the events are not independent: the first one has probability $\frac{6}{20}$, and the second one has probability $\frac{9}{19}$. Thus the probability is: $\frac{6}{20}\frac{9}{19}=\frac{27}{190}$
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