Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.6 Construct and Interpret Binomial Distributions - 10.6 Exercises - Mixed Review - Page 730: 63

Answer

See below

Work Step by Step

$$f(x)=3x^3-3x^2+75x-75=0\\3x^2(x-1)+75(x-1)=0\\(x-1)(3x^2+75)=0\\(x-1)(x^3+25)=0$$ Then we have: $x-1=0 \rightarrow x=1$ is the only solution of this equation.
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