Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - Guided Practice for Examples 2 and 3 - Page 718: 3

Answer

$\approx0.868$

Work Step by Step

Following the example: $P(\text{not hearing song})=\frac{_{11}C_4}{_{12}C_4}$ Hearing the songs on each day is independent, hence the probability we are looking for is: $P(\text{hearing song})=1-(\frac{_{11}C_4}{_{12}C_4})^5\approx0.868$
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