Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 Exercises - Skill Practice - Page 722: 28

Answer

See below.

Work Step by Step

a) In this case the events are independent: the first one has probability $\frac{12}{52}$, and the second one has probability $\frac{4}{51}$. Thus the probability is: $\frac{12}{52}\frac{4}{52}=\frac{3}{169}$ b) In this case the events are not independent: the first one has probability $\frac{12}{52}$, and the second one has probability $\frac{4}{51}$. Thus the probability is: $\frac{12}{52}\frac{4}{51}=\frac{4}{221}$
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