Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 Exercises - Problem Solving - Page 723: 39

Answer

$0.51$

Work Step by Step

The probability is: $P(\text{C})=P(\text{A and C})+P(\text{B and C})=P(A)P(C|A)+P(B)P(C|B)=0.55\cdot0.5+(0.47)(0.5)=0.51$
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