Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 Exercises - Problem Solving - Page 722: 37

Answer

$\approx0.807$

Work Step by Step

The chance of the bus coming early at least once is one minus the probability of it never coming early, which is $1−(1-0.28)^5$ because each day is independent. Thus the probability is: $1−(1-0.28)^5\approx0.807$
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