Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Finding Probabilities of Disjoint and Overlapping Events - Guided Practice for Examples 4 and 5 - Page 709: 8

Answer

$\approx0.0965$

Work Step by Step

Following the example: $P=1-\frac{100\cdot99\cdot98\cdot97\cdot96}{100^5}\approx0.0965$
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