Answer
5/6
Work Step by Step
We know that the probability of rolling a 7 is $1 - P(not 7)$.
Let us calculate the probability of getting a 7.
Our favorable outcomes are $[(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)]$
Those 6 divided by the sample space of 36 is $1/6$
$1-P(not7) = 1/6$
$P(not7 ) =5/6$
