Answer
$\approx0.04$
Work Step by Step
The probability is $1$ minus the probability of all of them having birthdays on different days, which is: $1-\frac{365\cdot364\cdot363\cdot362\cdot361\cdot360}{365^6}\approx0.04$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Problem Solving - Page 712: 48a
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