Answer
1
Work Step by Step
We know the following equation for permutations:
$$nP_r=\frac{n!}{(n-r)!}$$
Thus, we find:
$$nP_r=\frac{n!}{(n-0)!}=1$$
This makes sense because when $r$ is 0, there are 0 objects from the group, so there is only one way to organize them.