Answer
$$64x^3+144x^2y+108xy^2+27y^3$$
Work Step by Step
Multiplying the equation out, we find:
$$\left(4x\right)^3+3\left(4x\right)^2\cdot \:3y+3\cdot \:4x\left(3y\right)^2+\left(3y\right)^3\\ 64x^3+144x^2y+108xy^2+27y^3$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - 10.1 Apply the counting Principles and Permutations - 10.1 Exercises - Mixed Review - Page 689: 77
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