Answer
$y\gt-\frac{2}{3}$ or $y\lt-2$
Work Step by Step
$|3y+4|\gt2$ implies $3y+4\gt2\\3y\gt-2\\y\gt-\frac{2}{3}$ or $3y+4\lt-2\\3y\lt-6\\y\lt-2$.
Thus $y\gt-\frac{2}{3}$ or $y\lt-2$.
Then, by using a graphing utility, the solution set is attached.
