Answer
$x\gt\frac{c-b}{a}$ or $x\lt\frac{-c-b}{a}$.
Work Step by Step
$|ax+b|\gt c$ implies $ax+b\gt c\\ax\gt c-b\\x\gt\frac{c-b}{a}$ or $ax+b\lt -c\\ax\lt -c-b\\x\lt\frac{-c-b}{a}$.
Thus $x\gt\frac{c-b}{a}$ or $x\lt\frac{-c-b}{a}$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 1, Equations and Inequalities - 1.7 Solve Absolute Value Equations and Inequalities - 1.7 Exercises - Skill Practice - Page 56: 73
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
