Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.6 Solve Inequalities - Guided Practice for Examples 5,6, and 7 - Page 44: 13

Answer

The temperature of the lizard ranges from $59°F$ to $85°F$.

Work Step by Step

We have a lizard whose temperature ranges from $15°C$ to $30°C$. The range of temperatures in Celsius can be represented by the inequality: $15\leq C \leq 30$ To convert it into Fahrenheit, we will have to substitute $\frac{5}{9}(F-32)$ for $C$ $15\leq \frac{5}{9}(F-32) \leq 30$ To get rid of extra terms in the middle part, multiply each expression by $\frac{9}{5}$ $27\leq F-32 \leq 53$ Now add $32$ $59\leq F \leq 85$ The temperature of the lizard ranges from $59°F$ to $85°F$
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