Chapter 1, Equations and Inequalities - 1.5 Use Problem Solving Strategies and Models - 1.5 Exercises - Problem Solving - Page 39: 29

Piece 1 = 18 in. Piece 2 = 24 in. Piece 3 = 30 in.

Let $x=$ the first piece $x+6=$ the second piece $x+6+6=x+12=$ the third piece We are told that a piece of wood is 72 inches long: $x+x+6+x+12=72$ $3x+18=72$ $3x=54$ $x=18$ Therefore, piece 1 = 18 in. Piece 2 = 24 in. Piece 3 = 30 in.