Answer
$C=\dfrac{5}{9}(F-32)$ and $10^{\circ}$
Work Step by Step
As we are given that, $F-32=\dfrac{9}{5} C$
The formula for $C$ can be defined as:
$C=\dfrac{5}{9}(F-32)$
Plug $50^{\circ}$ for $F$
Then, we have
$C=\dfrac{5}{9}(50-32)=10^{\circ}$
Hence, $C=\dfrac{5}{9}(F-32)$ and $10^{\circ}$.
