Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Standardized Test Prep - Page 573: 50

Answer

D

Work Step by Step

$x^2-7x+3=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-7)±\sqrt {(-7)^2-4*1*3})/2*1$ $x=(7±\sqrt {49-12})/2$ $x=(7±\sqrt {37})/2$ $x=(7±\sqrt {37})/2$ $x=(7±6.08)/2$ $x=(7+6.08)/2$ $x = 13.08/2$ $x=6.54$ $x=(7-6.08)/2$ $x=.92/2 = .46$
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