Answer
D
Work Step by Step
$x^2-7x+3=0$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-(-7)±\sqrt {(-7)^2-4*1*3})/2*1$
$x=(7±\sqrt {49-12})/2$
$x=(7±\sqrt {37})/2$
$x=(7±\sqrt {37})/2$
$x=(7±6.08)/2$
$x=(7+6.08)/2$
$x = 13.08/2$
$x=6.54$
$x=(7-6.08)/2$
$x=.92/2 = .46$